{"id":17786,"date":"2024-04-09T08:24:27","date_gmt":"2024-04-09T08:24:27","guid":{"rendered":"https:\/\/soicau2096.minhngocxoso.com\/soi-cau-kep-kim-chinh-xac-100-moi-nhat-hien-nay\/"},"modified":"2024-04-09T08:24:27","modified_gmt":"2024-04-09T08:24:27","slug":"soi-cau-kep-kim-chinh-xac-100-moi-nhat-hien-nay","status":"publish","type":"post","link":"https:\/\/tinmatchotso.com\/soi-cau-kep-kim-chinh-xac-100-moi-nhat-hien-nay\/","title":{"rendered":"soi c\u1ea7u k\u1eb9p k\u00ecm ch\u00ednh x\u00e1c 100% m\u1edbi nh\u1ea5t hi\u1ec7n nay"},"content":{"rendered":"
Soi c\u1ea7u K\u1eb9p K\u00ecm ch\u00ednh x\u00e1c 100% m\u1edbi nh\u1ea5t hi\u1ec7n nay \u2013 \u00c1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u m\u1edbi nh\u1ea5t th\u1ef1c hi\u1ec7n soi c\u1ea7u l\u00f4 b\u1ea1ch th\u1ee7. website c\u1ee7a ch\u00fang t\u00f4i \u0111\u00e3 th\u1ef1c hi\u1ec7n ch\u00ednh x\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y v\u00e0 ho\u00e0n to\u00e0n d\u1ef1a v\u00e0o x\u00e1c su\u1ea5t. Mang l\u1ea1i k\u1ebft qu\u1ea3 v\u00f4 c\u00f9ng vi\u00ean m\u00e3n. Soi c\u1ea7u K\u1eb9p K\u00ecm ch\u00ednh x\u00e1c 100% m\u1edbi nh\u1ea5t hi\u1ec7n nay.<\/p>\n
Ph\u1ea3i n\u00f3i th\u00eam r\u1eb1ng, ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 ch\u00ednh x\u00e1c v\u00f4 c\u00f9ng cao. \u0110\u01b0\u1ee3c admin \u00e1p d\u1ee5ng th\u01b0\u1eddng xuy\u00ean trong vi\u1ec7c ch\u1ed1t s\u1ed1 gi\u1edd v\u00e0ng h\u00e0ng ng\u00e0y. Tin r\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd lu\u00f4n c\u00f3 m\u1eb7t trong s\u1ed5 soi c\u1ea7u l\u00f4 c\u1ee7a anh em.<\/p>\n
Ph\u1ea7n \u0111\u1ea7u ti\u00ean n\u00e0y ch\u00fang ta s\u1ebd c\u00f9ng t\u00ecm hi\u1ec3u xem nguy\u00ean l\u00fd th\u1ef1c hi\u1ec7n ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u1eb9p k\u00ecm nh\u01b0 th\u1ebf n\u00e0o. Anh em h\u00e3y n\u1eafm v\u1eefng l\u00fd thuy\u1ebft n\u00e0y \u0111\u1ec3 th\u1ef1c hi\u1ec7n cho ch\u00ednh x\u00e1c.<\/p>\n
Th\u1ed1ng k\u00ea trong 10 ng\u00e0y xem s\u1ed1 l\u1ea7n \u0110\u1ea7u, \u0110u\u00f4i v\u00e0 T\u1ed5ng n\u00e0o ra s\u1ed1 l\u1ea7n th\u1ea5p nh\u1ea5t v\u00e0 xu\u1ea5t hi\u1ec7n 21 l\u1ea7n tr\u1edf xu\u1ed1ng.<\/p>\n
Gi\u1ea3i th\u00edch: L\u00fd do ch\u00fang ta th\u1ed1ng k\u00ea 21 l\u1ea7n tr\u1edf xu\u1ed1ng l\u00e0 v\u00ec trung b\u00ecnh m\u00f5i ng\u00e0y xu\u1ea5t hi\u1ec7n 2,7 l\u1ea7n (\u0111\u1ea7u, t\u1ed5ng ho\u1eb7c \u0111u\u00f4i). N\u00ean 10 ng\u00e0y l\u00e0 27 l\u1ea7n, v\u00ec v\u1eady ch\u00fang ta ch\u1ecdn 21 l\u1ea7n l\u00e0 s\u1ed1 l\u1ea7n th\u1ea5p nh\u1ea5t m\u00e0 chu\u1ea9n nh\u1ea5t.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t: S\u1ebd lo\u1ea1i \u0111\u1ea7u (\u0111\u1ea7u, t\u1ed5ng) khi c\u00f3 2 \u0111\u1ea7u (\u0111u\u00f4i, t\u1ed5ng) tr\u1edf n\u00ean m\u00e0 c\u00f3 s\u1ed1 l\u1ea7n b\u00e9 nh\u1ea5t c\u00f9ng xu\u1ea5t hi\u1ec7n l\u00e0 21 l\u1ea7n. (chi ti\u1ebft ph\u1ea7n 2 n\u00f3i r\u00f5 h\u01a1n)<\/p>\n
Gh\u00e9p c\u00e1c \u0110\u1ea7u, \u0110u\u00f4i, T\u1ed5ng \u0111\u1ec3 t\u00ecm ra c\u00e1c L\u00f4 c\u00f3 kh\u1ea3 n\u0103ng n\u1ed5. B\u00ean c\u1ea1nh \u0111\u00f3, lo\u1ea1i L\u00f4 c\u00f3 t\u1ed5ng s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n (\u0111\u1ea7u + du\u00f4i + t\u1ed5ng) tr\u00ean 70 l\u1ea7n.<\/p>\n
V\u00ed d\u1ee5 \u00e1p d\u1ee5ng:<\/p>\n
<\/p>\n
Ch\u00fang ta \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c \u0110\u1ea7u s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n b\u00e9 nh\u1ea5t l\u00e0 \u0111\u1ea7u 5 = 21 l\u1ea7n, \u0110u\u00f4i s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n b\u00e9 nh\u1ea5t l\u00e0 \u0111u\u00f4i 3=20 l\u1ea7n, T\u1ed5ng s\u1ed1 l\u1ea7n ra b\u00e9 nh\u1ea5t l\u00e0 t\u1ed5ng 6= 19 l\u1ea7n.<\/p>\n
D\u1eef ki\u1ec7n ph\u1ee5: T\u1ed5ng 8 xu\u1ea5t hi\u1ec7n = 30 l\u1ea7n, \u0110u\u00f4i 1 xu\u1ea5t hi\u1ec7n = 23 l\u1ea7n. \u0110\u1ea7u 3 xu\u1ea5t hi\u1ec7n = 24 l\u1ea7n.<\/p>\n
Nh\u01b0 v\u1eady ta t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 51, 33 l\u00e0 c\u00e1c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n
Ch\u00fa \u00fd: C\u1ea7u \u0111\u1eb9p l\u00e0 l\u00f4 \u0111\u00f3 c\u00f3 t\u1ed5ng <=63. T\u1eeb 64 \u0111\u1ebfn 70 l\u00e0 c\u1ea7u trung b\u00ecnh.<\/p>\n
Anh em c\u1ea7n l\u1ef1a ch\u1ecdn ra 2 l\u00f4 trong c\u00e1c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao v\u00e0 tr\u00e1nh l\u00f4 gan v\u00e0 l\u00f4 v\u1eeba m\u1edbi ra \u0111\u1ec3 \u0111\u00e1nh: (tr\u00e1nh c\u00e1c l\u00f4 gan t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean v\u00e0 l\u00f4 v\u1eeba m\u1edbi ra)<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu ch\u1ec9 c\u00f3 2 l\u00f4 ph\u00f9 h\u1ee3p b\u01b0\u1edbc 3. Ta \u0111\u00e1nh 2 l\u00f4 \u0111\u00f3 trong 3 ng\u00e0y. Ch\u1ec9 \u0111\u00e1nh Max l\u00e0 3 ng\u00e0y.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu ch\u1ec9 1 l\u00f4 th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n b\u01b0\u1edbc 3. Th\u00ec ta tr\u00e1nh l\u00f4 \u0111\u00f3 n\u1ebfu gan t\u1eeb 7 ng\u00e0y tr\u1edf l\u00ean. V\u00e0 l\u00f4 \u0111\u00f3 t\u1ed5ng s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n <=63. Anh em s\u1ebd \u0111\u00e1nh b\u1ea1ch th\u1ee7 \u0111\u00f3 trong 6 ng\u00e0y.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 3: C\u00f3 nhi\u1ec1u h\u01a1n 2 l\u00f4 th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n b\u01b0\u1edbc 3. Ta ph\u1ea3i ch\u1ecdn ra 2 l\u00f4 \u0111\u00e1nh trong 3 ng\u00e0y.<\/p>\n
Tr\u00fang \u00edt nh\u1ea5t 1 l\u00f4 th\u00ec d\u1eebng nu\u00f4i. V\u00ed d\u1ee5 v\u1ec1 t\u1eebng tr\u01b0\u1eddng h\u1ee3p anh em s\u1ebd xem \u1edf ph\u1ea7n 2.<\/p>\n
Ch\u00fa \u00fd l\u00f4 gan: N\u1ebfu c\u1ea7u ra \u0111\u00e1nh b\u1ea1ch th\u1ee7 ta tr\u00e1nh nh\u1eefng l\u00f4 gan t\u1eeb 7 ng\u00e0y tr\u1edf l\u00ean. N\u1ebfu c\u1ea7u \u0111\u00e1nh song th\u1ee7 l\u00f4 th\u00ec tranh c\u00e1c l\u00f4 gan t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean. (Gi\u1ea3i th\u00edch: V\u00ec n\u1ebfu nu\u00f4i max ng\u00e0y th\u00ec c\u00e1c l\u00f4 n\u00e0y s\u1ebd tr\u1edf n\u00ean gan 13 ng\u00e0y, m\u00e0 l\u00f4 gan 13 ng\u00e0y tr\u1edf l\u00ean th\u00ec kh\u00f4ng n\u00ean \u0111\u00e1nh).<\/p>\n
Th\u00f4ng tin c\u1eadp nh\u1eadp<\/span>: Admin \u0111\u00e3 theo ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u00ecm k\u1eb9p n\u00e0y kh\u00e1 l\u00e2u. Tr\u00ean th\u1ef1c t\u1ebf th\u00ec \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u0169ng kh\u00f4ng ng\u1ea1i g\u00ec L\u00f4 Gan c\u1ea3. Nh\u01b0ng m\u00ecnh c\u1ee9 tr\u00e1nh \u0111i cho ch\u1eafc \u0103n. Anh em n\u00e0o v\u1ed1n nhi\u1ec1u v\u00e0 m\u00e1u li\u1ec1u cao th\u00ec c\u1ee9 nu\u00f4i c\u1ea3 l\u00f4 gan. C\u00f2n kh\u00f4ng th\u00ec tr\u00e1nh voi ch\u1eb3ng x\u1ea5u m\u1eb7t n\u00e0o.<\/p>\n Nh\u01b0 \u1edf b\u01b0\u1edbc 1 anh em \u0111\u00e3 hi\u1ec3u v\u1ec1 quy tr\u00ecnh \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u00ecm k\u1eb9p n\u00e0y. \u1ede b\u01b0\u1edbc th\u1ee9 2 n\u00e0y, ch\u00fang ta s\u1ebd \u0111i v\u00e0o t\u1eebng v\u00ed d\u1ee5 c\u1ee5 th\u1ec3. Ch\u00fang ta s\u1ebd c\u00f3 3 tr\u01b0\u1eddng h\u1ee3p th\u01b0\u1eddng g\u1eb7p nh\u1ea5t khi \u00e1p d\u1ee5ng.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p n\u00e0y n\u1ebfu ch\u00fang ta soi c\u1ea7u m\u00e0 kh\u00f4ng c\u00f3 tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t n\u00e0o c\u1ea3.<\/p>\n B\u01b0\u1edbc 1:<\/span> Truy c\u1eadp link th\u1ed1ng k\u00ea \u0111\u1ea7u \u0111u\u00f4i t\u1ed5ng<\/p>\n Anh em l\u1ef1a ch\u1ecdn kho\u1ea3ng 10 ng\u00e0y. V\u00ed d\u1ee5 nh\u01b0 k\u1ebft qu\u1ea3 b\u00ean d\u01b0\u1edbi.<\/p>\n Anh em nh\u1eadn th\u1ea5y c\u00e1c \u0111\u1ea7u \u0111u\u00f4i t\u1ed5ng th\u1ea5p nh\u1ea5t l\u00e0:<\/p>\n \u00c1p d\u1ee5ng theo l\u00fd thuy\u1ebft b\u00ean tr\u00ean ch\u00fang ta t\u00ecm \u0111\u01b0\u1ee3c c\u00e1c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng l\u00e0:<\/p>\n \u0110\u1ea7u \u0110u\u00f4i: 95. (\u0111\u1ea7u 9 =20 l\u1ea7n, \u0110u\u00f4i 5 =20 l\u1ea7n v\u00e0 T\u1ed5ng 4 =25 l\u1ea7n) => T\u1ed5ng = 21+20+25 = 66 l\u1ea7n.<\/p>\n \u0110\u1ea7u T\u1ed5ng: 91 => T\u1ed5ng = 20 + 19 + 35 (\u0111u\u00f4i 1) = 74 l\u1ea7n.<\/p>\n \u0110u\u00f4i T\u1ed5ng: 55 => T\u1ed5ng = 20 + 19 + 28 = 67 l\u1ea7n.<\/p>\n K\u1ebft Qu\u1ea3: Ch\u1ecdn 95 v\u00e0 55. Lo\u1ea1i 91 v\u00ec c\u00f3 74 l\u1ea7n > 70.<\/p>\n B\u01b0\u1edbc 2<\/span>: Ki\u1ec3m tra L\u00f4 c\u00f3 kh\u1ea3 n\u0103ng c\u00f3 v\u1eeba m\u1edbi v\u1ec1 kh\u00f4ng.<\/p>\n B\u00ean tr\u00ean ch\u00fang ta \u0111\u00e3 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u00ecm k\u1eb9p v\u00e0 c\u00f3 \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0 c\u1eb7p 95 v\u00e0 55. B\u00e2y gi\u1edd anh em h\u00e3y xem k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y h\u00f4m qua v\u00e0 xem c\u00f3 ra 2 c\u1eb7p l\u00f4 n\u00e0y kh\u00f4ng.<\/p>\n K\u1ebft qu\u1ea3: Kh\u00f4ng c\u00f3 95 v\u00e0 55 th\u00ec v\u1eabn th\u1ecfa m\u00e3n.<\/p>\n B\u01b0\u1edbc 3<\/span>: Th\u1ed1ng k\u00ea l\u00f4 gan t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean<\/p>\n Anh em s\u1ebd \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p th\u1ed1ng k\u00ea l\u00f4 gan \u1edf link b\u00ean tr\u00ean. Ki\u1ec3m tra trong 10 ng\u00e0y li\u00ean ti\u1ebfp xem c\u00f3 2 con l\u00f4 95 v\u00e0 55 kh\u00f4ng.<\/p>\n K\u1ebft qu\u1ea3: C\u1ea3 2 c\u1eb7p l\u00f4 \u0111\u1ec1u kh\u00f4ng thu\u1ed9c di\u1ec7n Gan.<\/p>\n Nh\u01b0 v\u1eady, ch\u00fang ta s\u1ebd \u0111\u00e1nh 95 v\u00e0 55 trong Max 3 ng\u00e0y. Anh em m\u1ea1nh tay n\u1ebfu mu\u1ed1n \u0103n \u0111\u1eadm.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p soi c\u1ea7u k\u00ecm k\u1eb9p m\u00e0 ta \u0111\u00e3 lo\u1ea1i h\u1ebft t\u1ea5t c\u1ea3 c\u00e1c l\u00f4 v\u00e0 ch\u1ec9 c\u00f2n l\u1ea1i m\u1ed9t l\u00f4 duy nh\u1ea5t th\u1ecfa m\u00e3n th\u00ec x\u00e9t ti\u1ebfp c\u00e1c \u0111i\u1ec1u ki\u1ec7n sau:<\/p>\n V\u00ed d\u1ee5: Ta x\u00e9t \u0111\u1ea7u \u0111u\u00f4i t\u1ed5ng ng\u00e0y 14\/03\/2024.<\/p>\n Ch\u00fang ta t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao nh\u01b0 sau:<\/p>\n Ph\u00e2n t\u00edch ti\u1ebfp l\u00f4 gan tr\u00ean 10 ng\u00e0y v\u00e0 l\u00f4 v\u1eeba m\u1edbi v\u1ec1 th\u1ea5y 49, 85 v\u1eeba m\u1edbi ra. N\u00ean ch\u1ec9 c\u00f2n l\u00f4 45 l\u00e0 th\u1ecfa m\u00e3n v\u1edbi \u0111i\u1ec1u ki\u1ec7n.<\/p>\n X\u00e9t ti\u1ebfp n\u1ebfu l\u00f4 45 gan tr\u00ean 7 ng\u00e0y th\u00ec kh\u00f4ng \u0111\u00e1nh. Th\u1ea5y 45 m\u1edbi gan 1 ng\u00e0y n\u00ean th\u1ecfa m\u00e3n.<\/p>\n X\u00e9t th\u1ea5y 45 c\u00f3 T\u1ed5ng =60 <63 (b\u1eb1ng 63 v\u1eabn \u0111\u01b0\u1ee3c) => \u0110\u00e1nh l\u00f4 45 trong 6 ng\u00e0y.<\/p>\n Trong 6 ng\u00e0y n\u00e0y b\u1ea3o \u0111\u1ea3m anh em s\u1ebd \u0103n l\u00f4 45 \u00edt nh\u1ea5t 2 l\u1ea7n.<\/p>\n Khi xu\u1ea5t hi\u1ec7n nhi\u1ec1u s\u1ed1 l\u1ea7n b\u00e9 nh\u1ea5t b\u1eb1ng nhau tr\u00ean c\u00f9ng 1 d\u1eef ki\u1ec7n (\u0110\u1ea7u, \u0110u\u00f4i ho\u1eb7c T\u1ed5ng) (v\u00ed d\u1ee5 c\u00f3 2 \u0110\u1ea7u \u0111\u1ec1u l\u00e0 20 l\u1ea7n ch\u1eb3ng h\u1ea1n) th\u00ec ta gh\u00e9p \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u s\u1ed1, v\u00e0 c\u0169ng r\u1ea5t nhi\u1ec1u s\u1ed1 th\u1ecfa m\u00e3n T\u1ed5ng <=70 v\u00e0 l\u00e0 l\u00f4 gan 1 ng\u00e0y \u0111\u1ebfn 9 ng\u00e0y (tr\u00e1nh l\u00f4 v\u1eeba m\u1edbi ra v\u00e0 l\u00f4 gan t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean) th\u00ec ta ph\u1ea3i ch\u1ecdn ra 2 con \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n \u01afu ti\u00ean<\/span>: Ch\u1ecdn nh\u1eefng l\u00f4 c\u00f3 s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n T\u1ed5ng l\u00e0 b\u00e9 nh\u1ea5t.<\/p>\n V\u00ed d\u1ee5: Ta x\u00e9t \u0111\u1ea7u \u0111u\u00f4i t\u1ed5ng ng\u00e0y 25\/03\/2024. Sau khi th\u1ed1ng k\u00ea, ch\u00fang ta t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao nh\u01b0 sau:<\/p>\n X\u00e9t th\u1ea5y l\u00f4 68, 61, 98 \u0111\u1ec1u \u0111\u1ee7 \u0111i\u1ec1u ki\u1ec7n l\u00f4 gan t\u1eeb 1 \u0111\u1ebfn 9 ng\u00e0y v\u00e0 c\u00f3 t\u1ed5ng < 71. => Ta ch\u1ec9 l\u1ef1a ch\u1ecdn 2 l\u00f4 c\u00f3 t\u1ed5ng xu\u1ea5t hi\u1ec7n b\u00e9 nh\u1ea5t l\u00e0 68 t\u1ed5ng = 55 l\u1ea7n, v\u00e0 98 t\u1ed5ng =64 l\u1ea7n.<\/p>\n K\u1ebft qu\u1ea3: \u0110\u00e1nh 68,98 trong 3 ng\u00e0y. B\u1ea3o \u0111\u1ea3m r\u1ef1c r\u1ee1<\/p>\n Trong ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u1eb9p k\u00ecm n\u00e0y. C\u00f3 m\u1ed9t tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t c\u1ea7n Lo\u1ea1i \u0110\u1ea7u (\u0111u\u00f4i, t\u1ed5ng) khi c\u00f3 2 \u0111\u1ea7u (\u0111u\u00f4i, t\u1ed5ng) tr\u1edf l\u00ean c\u00f3 s\u1ed1 l\u1ea7n b\u00e9 nh\u1ea5t c\u00f9ng xu\u1ea5t hi\u1ec7n l\u00e0 21 l\u1ea7n.<\/p>\n Anh em l\u01b0u \u00fd: Ch\u00fang ta ch\u1ec9 b\u1ecf D\u1eef Ki\u1ec7n, ch\u00fang ta kh\u00f4ng lo\u1ea1i lu\u00f4n ng\u00e0y h\u00f4m \u0111\u00f3. B\u00ean c\u1ea1nh \u0111\u00f3 anh em c\u0169ng l\u01b0u \u00fd l\u00e0 n\u1ebfu ch\u1ec9 c\u00f3 1 \u0111\u1ea7u (\u0111u\u00f4i, t\u1ed5ng) b\u00e9 nh\u1ea5t l\u00e0 21 l\u1ea7n h\u00ec v\u1eabn \u0111\u01b0\u1ee3c ch\u1ecdn (ch\u1ec9 2 tr\u1edf l\u00ean m\u1edbi lo\u1ea1i).<\/p>\n V\u00ed d\u1ee5: X\u00e9t ng\u00e0y 20\/03\/2024 ta th\u1ed1ng k\u00ea \u0111\u1ea7u \u0111u\u00f4i t\u1ed5ng c\u00f3 k\u1ebft qu\u1ea3 nh\u01b0 sau:<\/p>\n X\u00e9t \u1edf \u0110u\u00f4i, ta th\u1ea5y 2 \u0110u\u00f4i 6, \u0110u\u00f4i 9 \u0111\u1ec1u l\u00e0 th\u1ea5p nh\u1ea5t l\u00e0 21 l\u1ea7n.<\/p>\n => Ta s\u1ebd lo\u1ea1i \u0110u\u00f4i n\u00e0y v\u00ec kh\u00f4ng th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n.<\/p>\n L\u01b0u \u00fd: Ta v\u1eabn t\u00ecm ra \u0111\u01b0\u1ee3c c\u00e1c l\u00f4 kh\u1ea3 n\u0103ng d\u1ef1a v\u00e0o 2 d\u1eef ki\u1ec7n \u0110\u1ea7u v\u00e0 T\u1ed5ng c\u1ee7a tr\u01b0\u1eddng h\u1ee3p n\u00e0y l\u00e0 \u0110\u1ea7u 1, \u0110\u1ea7u 6 v\u00e0 T\u1ed5ng 9 => L\u00f4 18, 63. Ch\u1ee9 kh\u00f4ng b\u1ecf h\u1eb3n nh\u00e9, ch\u1ec9 b\u1ecf ph\u1ea7n \u0110u\u00f4i th\u00f4i.<\/p>\n B\u00ean tr\u00ean l\u00e0 to\u00e0n b\u1ed9 l\u00fd thuy\u1ebft v\u00e0 tr\u1ef1c h\u00e0nh tr\u1ea3i nghi\u1ec7m th\u1ef1c t\u1ebf cho ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u00ecm k\u1eb9p n\u00e0y. B\u00e0i vi\u1ebft n\u00e0y kh\u00e1 d\u00e0i v\u00e0 ph\u1ee9c t\u1ea1p n\u1ebfu nh\u01b0 anh em ch\u1ec9 \u0111\u1ecdc qua th\u00ec kh\u00f3 hi\u1ec3u. Anh em h\u00e3y \u0111\u1ecdc ch\u1eadm, t\u1eeb t\u1eeb th\u1ef1c h\u00e0nh t\u1eebng b\u01b0\u1edbc 1. Anh em n\u00ean nh\u1edb r\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 ch\u00ednh x\u00e1c l\u00ean \u0111\u1ebfn 100%. V\u00ec v\u1eady h\u00e3y th\u1ef1c h\u00e0nh c\u1ea9n th\u1eadn.<\/p>\n N\u1ebfu anh em c\u1ea3m th\u1ea5y kh\u00f3 hi\u1ec3u \u1edf b\u1ea5t k\u1ef3 b\u01b0\u1edbc n\u00e0o. H\u00e3y \u0111\u1ec3 l\u1ea1i b\u00ecnh lu\u1eadn b\u00ean d\u01b0\u1edbi. Admin s\u1ebd gi\u00fap b\u1ea1n gi\u1ea3i \u0111\u00e1p. Ch\u00fac anh em may m\u1eafn c\u00f9ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y.<\/p>\n2. C\u00e1c tr\u01b0\u1eddng h\u1ee3p soi c\u1ea7u k\u1eb9p k\u00ecm n\u00ean nh\u1edb<\/h4>\n
<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 1 \u2013 N\u1ebfu ch\u1ec9 c\u00f3 2 l\u00f4 ph\u00f9 h\u1ee3p<\/h5>\n
\n
<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 2 \u2013 N\u1ebfu ch\u1ec9 c\u00f3 1 l\u00f4 th\u1ecfa m\u00e3n<\/h5>\n
\n
\n
Tr\u01b0\u1eddng h\u1ee3p 3: C\u00f3 nhi\u1ec1u h\u01a1n 2 l\u00f4 th\u1ecfa m\u00e3n<\/h5>\n
\n
<\/p>\n
3. Tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t khi soi c\u1ea7u k\u1eb9p k\u00ecm<\/h4>\n
K\u1ebft Th\u00fac<\/h4>\n
ch\u1ed1t s\u1ed1 mi\u1ec1n b\u1eafc
<\/span><\/h2>\n